Question

if the sinA=1/2 find the value of cosA×cosecA+ tanA × secA​

Answer 1

Given

⇒SinA = 1/2

To Find Value

⇒CosA×CosecA + TanA×SecA

Now Take

⇒SinA = 1/2

⇒A= Sin⁻¹(1/2)

⇒A= 30°

Now Put the value A= 30°

⇒Cos30°×Cosec30° + Tan30°×Sec30°

⇒Cos30°×1/Sin30° + Tan30° × Sec30°

⇒Cot30° + Tan30°×Sec30°

We Know That

⇒Cot30° = (√3)

⇒Tan30° = 1/(√3)

⇒Sec30° = 2/(√3)

Now put the value

⇒Cot30° + Tan30°×Sec30°

⇒(√3) + 1/(√3)× 2/(√3)

⇒√3 +  2/3

⇒(3√3 + 2 )/3

Answer

⇒(3√3 + 2 )/3