If the sixth term of the parallel series and the 17th term are 19 and 41 respectively, find the 40th term.
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Answer:
a+5d= 19........i
a+16d=41........ii
from i and ii
11d =22
d=2
putting the value of d in i.
a+10=19
a=9
40th term = a+ (40 - 1) d
=9+39×2
=78+9
=87
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