Question

If the size of the sample is 5 and size of the population the correction factor is what

Answer 1

Answer:

Thirty people from a population of 300 were asked how much they had in savings. The sample mean (with a sample standard deviation of $89.55. Construct a 95% confidence interval estimate for the population mean.

Solution (using degrees of freedom = n – 1 = 29) and tα/2 = 2.0452 for a 95% confidence level):

Answer 2

Answer:

hope it this correct answer