Question

If the sizes of the interior angles of a hexagon are x,2x.3x,4x,6xand 8x. Find the largest interior angle.plss tell this

Answer 1

Step-by-step explanation:

Formula of sum of all interior angles of a polygon is=(n-2)x180°

so,for a hexagon it will be (6-2)x180°=720°...

A/Q

x+2x+3x+4x+6x+8x =720°

24x=720°

x=30°

so largest interior will be 8x,

8x30=240° ....ans

Answer 2

$\huge\bold{Solution}$

Formula of sum of all interior

of a polygon is = $\boxed{\red{\bf{(n-2)×180}}}$

So, far a hexagon it will be...

(6-2) × 180° = $\boxed{\red{\bf{720°}}}$

A/Q

x+2x+3x+4x+6x+8x = $\boxed{\red{\bf{720°}}}$

24x = $\boxed{\red{\bf{720°}}}$

x = 30°

so largest interior will be 8x,

8×30 = $\boxed{\red{\bf{240°}}}$ ans

${\huge{\underline{\small{\mathbb{\red{HOPE\:HELP\:U\:BUDDY :)}}}}}}$