Question

If the sizes of the interior angles of a pentagon are 2r, 3r, 4x, 5x and 6x, find the largest interior angle of the pentagon.

pls answer this thank youu​

Answer 1

Answer:

sunm of all angles of a pentagon =540°

2x+3x+4x+5x+6x=540°

20x=540°

X=540/20

X=27

largest interior angle =6(27)=162

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Step-by-step explanation:

Answer 2

Answer:

• 162

Step-by-step explanation:

Explanation :

recall the property of Pentagon

The sum of all interior angle in a Pentagon is equal to 540 .

since:

2x+3x+4x+5x+6x=540

solving for x

2x+3x+4x+5x+6x=540

20x=540

x=540/20

x=27

The largest interior angle is

6x

=6 x 27

=162