if the sizes of the interior angles of a pentagon are 2x ,3x, 4x, 5x, and 6x find the ;largest interior angle of the pentagon
Answers
Answered by
72
Answer:
162
Step-by-step explanation:
Angle sum property
2X+3X+4X+5X+6X=540
20X=540
X=27
So the largest angle will be 6(27)=162
Hope it helps you
Answered by
49
Answer:
sunm of all angles of a pentagon =540°
2x+3x+4x+5x+6x=540°
20x=540°
X=540/20
X=27
largest interior angle =6(27)=162
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