Math, asked by zuizzrizwany5, 1 year ago

if the sizes of the interior angles of a pentagon are 2x ,3x, 4x, 5x, and 6x find the ;largest interior angle of the pentagon

Answers

Answered by sohanreddysathi
72

Answer:

162

Step-by-step explanation:

Angle sum property

2X+3X+4X+5X+6X=540

20X=540

X=27

So the largest angle will be 6(27)=162

Hope it helps you

Answered by VishnuPriya2801
49

Answer:

sunm of all angles of a pentagon =540°

2x+3x+4x+5x+6x=540°

20x=540°

X=540/20

X=27

largest interior angle =6(27)=162

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