Question

if the sizes of the interior angles of a triangle are 3x,5x and 4x,find the smallest angle of the triangle.

Answer 1

Answer:

45°

Step-by-step explanation:

Sum of internal angles of a triangle = 180°

Therefore,  3x + 4x + 5x = 180

                             ⇒ 12x = 180

                                 ⇒ x = 180 ÷ 12 = 15

Smallest angle = 3x  ⇒   3 x 15 = 45°

Answer 2

Answer:

If the sizes of the interior angles of a triangle are 3x, 5x and 4x, then the smallest angle of the triangle is 45°.

Step-by-step explanation:

Given: The interior angles of a triangle are 3x, 5x and 4x.

Find the smallest angle of the triangle.

The sum of the angle of the triangle is 180°.

3x + 5x + 4x = 180°

(3 + 5+ 4)x = 180°

12x = 180°

x = 180/12

x = 15°

So, first angle = 3x = 3(15) = 45°

Second angle = 5x = 5(15) = 75°

And third angle = 4x = 4(15) = 60°

So, the smallest angle of the triangle is 45°.