English, asked by sajithasunil, 9 months ago

if the slant height of a frustum cone is 10 cm and the perimeter of its circular base are 18 cm and 28 CM respectively what is the curved surface area of the frustum​

Answers

Answered by shamsheraghai
0

Answer:

curved surface area of cone= pie radius slant height so the area is

pue=22 divide by7

slant height = 10

radius= 20.04

so, answer is

629.8

Answered by muscardinus
4

The curved surface area of the frustum​  is 229.65\ cm^2.

Explanation:

Given that,

The slant height of a frustum cone, l = 10 cm

The perimeter of the circular base is 18 cm.

2\pi r = 18\\\\r=2.86\ cm

The  perimeter of the circular base is 28 cm.

2\pi R = 28\\\\R=4.45\ cm

The curved surface area of the frustum of a cone is given by :

C=\pi l(r+R)\\\\C=\pi \times 10(2.86+4.45)\\\\C=229.65\ cm^2

So, the curved surface area of the frustum​  is 229.65\ cm^2. Hence, this is the required solution.

Learn more,

Curved surface area of the frustum

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