Question

if the slope of the line joining P (k,3) and Q (8,-6) is -3/4, find the value of k

Answer 1

Answer:

Step-by-step explanation:

Given that,

Points on a line are P ( x1 , y1 ) = ( k , 3 ) and Q ( x2 , y2 ) = ( 8 , - 6 )

and slope = m = - 3/4

∴ Slope of the line= m = y2 - y1 / x2 - x1

⇒ - 3/4 = - 6 - 3 / 8 - k

⇒ - 3/4 = - 9/ 8 - k

⇒ - 3 ( 8 - k ) = 4 ( - 9 )

⇒ - 24 + 3k = - 36

⇒ 3k = - 36 + 24

⇒ 3k = - 12

⇒ k = - 12 / 3

⇒ k = - 4 is the answer

Answer 2

Given:

Slope: -3/4

P(k,1)

Q(8,-6)

k=?

Solution:

=>-3/4 = -6-3/8-k

(using the formula m=(y2-y1(/(x2-x1)

=> -24+3k= -24-12

=> 3k=-24+24-12

=> k=12/-3

=> k=-4