Question

if the smaller of the two consecutive even integers is subtracted from three times the larger result is 42 find the integer​

Answer 1

${\huge{\pink{\underline{\underline{Answer:}}}}}$

Let the 1st even integer be = x

Let the 2nd even integer be = x + 2

Let the 3rd even integer be = x + 4

$\mathbb\red{According..to..the..problem}$

3 (largest even Number) - (smaller Numbers) = 42

3 ( x + 4 ) - ( x + x + 4 ) = 42

3 ( x + 4 ) - 2x - 2 = 42

3x + 12 -2x - 2 = 42

x + 10 = 42

x = 42 - 10

x = 32

$\mathbb\green{x = 32}$

So :

1st Number = x = 32

2nd Number = x + 2 = 32+2 = 34

3rd Number = x + 4 = 32 + 4 = 36

Answer 2

Answer:

1 St number:32

2 nd number: 34

3rd number:36