if the smallest number of the Pythagorean triplets is 6 what is the other two numbers
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We all know that m>1 so 2m,(m^2)-1 (m^2+1)
So,According to the property of Pythagorean triplet, Here M=6
so, 2m=
M=6/2 = 3
m^2-1=9-1=8
m^2+1=9+1=10
So, the Pythagorean triplet is 6,8 and 10...
Hope it helped!!
Thanks
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