Physics, asked by VickyBommella7205, 11 months ago

If the solar constant is 1.4 kW/m2, then the solar energy received by 1 m2 area in one hour is :; A. 5040 J; B. 504.0 Kj; C. 5040 Kj; D. 5.04 Kj

Answers

Answered by hannjr
6

Answer:

1.4 kW/m^2 = (1.4 kJ) / (sec m^2)

(1.4 kJ) / (sec m^2) * 3600 sec / hr = (5040 kJ) / (hr m^2)

Answered by harman7934
3

Answer:

S

Explanation:

The answer is solar constants is 1.4kw/msqaure so 1 hour is 3600second so 1.4x3600= 5040 kj hope this help yu ...

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