Question

If the solutions of the equation x² + 3x – 18 = 0 are –6, 3, then the roots of the equation 2(x² + 3x – 18) = 0 are __________. ​

Answer 1

Answer:

x= -6 and 3

Explanation of the same:-

$2(x^2 + 3x -18) = 0\\2(x^2 +6x-3x-18)=0\\2 [ x(x+6) - 3(x+6)]=0\\2(x+6)(x-3)=0\\\\Now, either 2(x+6)=0, or, 2(x-3)=0\\i) 2x+12=0 => x=-6\\ii) 2x-6=0 => x=3$

Therefore the roots are unequal and real.