Question

If the solutions of the equation x² + 3x – 18 = 0 are –6, 3, then the roots of the equation 2(x² + 3x – 18) = 0 are __________.​

Answer 1

Answer:

-6 and 3 are the roots.

Step-by-step explanation:

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Answer 2

$2( {x}^{2} + 3x - 18) = 0$

So,when 2 is substituted by 0

Then our equation is

${x }^{2} + 3x - 18 = 0$

So, by factorisation method

${x}^{2} + (6 - 3)x - 18 = 0$

18 × 1 = 0

Toh hame aise digit pta lagani hai jisse multiply karne par 18 aaye aur plus ya minus karne par 3

Toh

6 - 3 = 3

6 × 3 = 18

${x}^{2} + 6x - 3x - 18 = 0$

$x(x + 6) - 3(x + 6) = 0$

$(x + 6)(x - 3) = 0$

If

$x + 6 = 0 \\ x = - 6$

If

$x - 3 = 0 \\ x = 3$

So the roots are -6 and 3