Question

If the specific heat of ice is 0.5 calories per gram degree Celsius, find the value in SI

system?​

Answer 1

Answer:

Explanation:

The problem provides you with the specific heat of ice, which is said to be equal to

c

ice

=

0.5 cal g

−

1

∘

C

−

1

=

0.5

a

cal

g

∘

C

As you can see, specific heat is expressed in units of energy, in this case calories, per gram Celsius, which means that a substance's specific heat tells you how much energy is needed to increase the temperature of

1 g

of said substance by

1

∘

C

.

For ice, you know that if you provide

0.5

calories of heat to

1 g

of ice you will increase its temperature by

1

∘

C

.

This is how much heat you need to supply to a given sample of ice for every gram and for every

1

∘

C

increase in temperature.

To increase the temperature of

20 g

of ice by

1

∘

C

, you need to provide it with

0.5 cal

for every gram. This will cause its temperature to increase by

1

∘

C

.

20

g

⋅

0.5 cal

∘

C

−

1

1

g

=

10 cal

∘

C

−

1

For a

1

∘

C

increase in temperature, you have

1

∘

C

⋅

10 cal

1

∘

C

=

∣

∣

∣

∣

¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯

a

a

10 cal

a

a

∣

∣

−−−−−−−−−

As you can see, to increase the temperature of this sample by more than

1

∘

C

you need to provide it with

10 cal

of heat for every

1

∘

C

increase in temperature.

For example, to increase the temperature of

20 g

of ice by

3

∘

C

, you need to provide it with