if the speed of a body is halved,what will be the change in its kinetic energy?
please answer
Answers
Answered by
1
Answer is
K/K' = v*2/ (v/2)*2
K/K' = 4
K' = K/4
Kinetic energy becomes one fourth.
I hope it helps
Answered by
2
Hey siso Ru there ??
wat's ur exam 2morrow ??
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