Question

if the speed of a bus is increased by 5 km hr from its normal speed it takes 2hr less for a journey of 300km the normal speed of bus (in km/hr

Answer 1

let the original speed of bus is x.
time =distance÷speed
according to question
300/x - 300/(x+5) =2
300(1/x -1/x+5)=2
5/x(x+5)=1/150
$x { }^{2} + 5x - 750= 0$
(x-25)(x+30)=0
x=25 ,x= - 30
speed never be negative so
x=25

Answer 2

Answer:let the original speed of bus is x.

time =distance÷speed

according to question

300/x - 300/(x+5) =2

300(1/x -1/x+5)=2

5/x(x+5)=1/150

x { }^{2} + 5x - 750= 0

(x-25)(x+30)=0

x=25 ,x= - 30

speed never be negative so

x=25

Step-by-step explanation:

Mark as brainliest