If the speed of a car is decreased by 12 km/h, it takes 1 hour more to cover a
distance of 240 km. Find the original speed of the car.
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Answer:
Step-by-step explanation:
Let the speed of the car be x km per hour
Distance = 240 km
Speed of car = x km per hour
Time = Distance/speed
Time = 240/x
If the speed of the car is decreased by 8 km per hour, it takes 1 hour more to cover a distance of 240 km
Time during changed speed
= 240 km /x - 8 km per hour
240/(x - 8) - 240/x = 1 hour
240x —240 (x - 8)/ x (x - 8) = 1 hour
240x — 240x + 1920/ x^2 - 8x = 1 hour
1920/x^2 - 8x = 1 hour
Cross multiplication
x^2 - 8x = 1920
x^2 - 8x -1920 = 0
x^2 - 48x + 40 x - 1920
x (x - 48) + 40 (x - 48)
(x + 40) (x - 48)
x = —40 is not possible being negative hence discarded
x = 48 km per hour
The original speed of the car was 48 km per hour
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