If the speed of a car is decreased by 8 km/h, it takes 1 hour more to cover a
distance of 240 km. Find the original speed of the car.
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Let the speed of car be xkmph
Let it takes Time t hrs to cover the distance of 240km
⟹xt=240⋯(1)
speed is decreased by 8⟹x−8
Time is increased by 1⟹t+1
it covers the same distance so (x−8)(t+1)=240
xt+x−8t−8=240
From (1)⟹x−8t−8=0
x=8t+8
Put it in (1)⟹(8t+8)(t)=240
t ²+t−30=0
t ²+6t−5t−30=0
t(t+6)−5(t+6)=0
(t−5)(t+6)=0
t=5,−6
Time cannot be negative so t=5
Put it in (1)
⟹x(5)=240⟹x=12kmph
I hope it help you..
vedantthake2006:
cutiya
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