If the speed of a car is decreased by 8km/h, it takes 1 hour more to cover a distance of 240km. find the original speed of the car
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If the speed of the car is decreased by 8 km per hour, it takes 1 hour more to cover a distance of 240 km. What is the original speed of the car?
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4 Answers

C. S. Sharma, Most Viewed Writer, Quora, Mathematics Word Problems
Answered January 16, 2020
Friends….!
Let the speed of the car be x km per hour
Distance = 240 km
Speed of car = x km per hour
Time = Distance/speed
Time = 240/x
If the speed of the car is decreased by 8 km per hour, it takes 1 hour more to cover a distance of 240 km
Time during changed speed
= 240 km /x - 8 km per hour
240/(x - 8) - 240/x = 1 hour
240x —240 (x - 8)/ x (x - 8) = 1 hour
240x — 240x + 1920/ x^2 - 8x = 1 hour
1920/x^2 - 8x = 1 hour
Cross multiplication
x^2 - 8x = 1920
x^2 - 8x -1920 = 0
x^2 - 48x + 40 x - 1920
x (x - 48) + 40 (x - 48)
(x + 40) (x - 48)
x = —40 is not possible being negative hence discarded
x = 48 km per hour
The original speed of the car was 48 km per hour
Answer : the original speed of the car was 48 km per hour
773 views · Answer requested by Prakash Kumar

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Biju P.S, former 15 Years Experience in Sales in FMCG Companies
Answered January 16, 2020
Let s & t be the original speed & time taken.
So s×t = 240
t = 240/s
Also (s - 8)(t+1) = 240
st+s-8t-8 = 240
Applying the value of st & t in above equation
240+s-8×240/s-8 = 240
s -1920/s = 8
s²-1920 = 8s
s²-8s-1920 = 0
(s-48)(s+40) = 0
So s = 48 or -40
Since s can not be negative, s = 48
So original speed of the car is 48 km/hr
108 views
Answer:
Let the speed of car be xkmph
Let it takes Time t hrs to cover the
distance of 240km
⟹xt=240⋯(1)
speed is decreased by 8⟹x−8
Time is increased by 1⟹t+1
it covers the same distance so (x−8)(t+1)=240
xt+x−8t−8=240
From (1)⟹x−8t−8=0
x=8t+8
Put it in (1)⟹(8t+8)(t)=240
t ² +t−30=0
t ²+6t−5t−30=0
t(t+6)−5(t+6)=0
(t−5)(t+6)=0
t=5,−6
Time cannot be negative so t=5
Put it in (1)
⟹x(5)=240⟹x=12kmph
I hope it help you..