Question

if the speed of a car is increased by 10 km/hr. it takes one and half hours less to cover a journey of 450 km.Find the original speed of the car

Answer 1

Let speed of car =x

Actual time taken by car =450/x

time taken when speed is increased by 10 km/h= 450/[x+10]

450/[x+10] + 3/2 = 450/x

[900+3x+30]x=900x+9000

900x+3x*x+30x=900x+9000

3x*x+30x-9000=0

x*x+10x-3000=0

x=50km/h

Answer 2

Hey mate!!

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Let speed of car =x

Actual time taken by car =450/x

time taken when speed is increased by 10 km/h= 450/[x+10]

450/[x+10] + 3/2 = 450/x

[900+3x+30]x=900x+9000

900x+3x × x + 30x=900x + 9000

3x × x + 30x - 9000=0

x × x+10x-3000=0

x=50km/h

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Thanks for the question!!

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