If the speed of a car is increased by 10km/hr, it takes 1 hour less to cover a distance of 300km then find the original speed of the car
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Answer:
DISTANCE = 300 KM
LET , SPEED = X
SO, 300/X - 300/X+10 = 1
===> 300X+3000-300X / X²+10X = 1
==> 3000 = X²+10X
==> 0 = X²+10X-3000
==> 0 = X²+60X-50X-3000
==> X(X+60)-50(X+60)
==> (X+60) (X-50)
==> X = -60;50
SO, SPEED = 50 KM/H
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