If the speed of a particle is increased by 2 times, how will its kinetic energy be affected? Show by calculation
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Answer:
K.E' = 4 K.E
K.E increases to 4 times
Explanation:
K.E = 1/2 mv² .......( 1 )
v' = 2v putting in Eq.1
K.E' = 1/2 m (2v)²
K.E' = 1/2 m (4v²)
K.E' = 4 (1/2 mv²)
K.E' = 4 K.E
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