If the speed of an electron is measured with an accuracy of 50 ±1 m/sec, then the minimum time (in us) required to measure the kinetic energy
of the electron is
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Answer:
By applying the uncertainty principle,
ΔP=
4πΔx
h
=
4×3.1416×0.002×10
−9
6.626×10
−34
=2.63×10
−23
kg m/s
The uncertainty in momentum is,
4πm×0.002×10
−9
h
=
4×π×m
h×5×10
11
.
This is much larger than the actual momentum, i.e,
4πm
h
×0.05 nm. Hence, it cannot be defined
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