Question

If The Speed Of light Is 3.0×10^8 m/s , Calculatethe distance covered by light in 2.00ns.

❎No Spam❎
❎No copied answer❎​

Answer 1

Given :

Speed of light = 3X10⁸ ms ¹

Time= 2.00 nsec = 2X10 ⁹s

As we know

Distance covered= Speed X Time

The distance traveled is the product of Speed and Time

Thus in 2.00nsec, the light will travel a distance of

$3.00 \times 10 ms \times 2.00 \times 10s = 0.600m$

Answer 2

Answer:

Given :

Given :Speed of light =3×10

Given :Speed of light =3×10 8

Given :Speed of light =3×10 8 ms

Given :Speed of light =3×10 8 ms −1

Given :Speed of light =3×10 8 ms −1

Given :Speed of light =3×10 8 ms −1 Times=2.00 nsec=2×10

Given :Speed of light =3×10 8 ms −1 Times=2.00 nsec=2×10 −9

Given :Speed of light =3×10 8 ms −1 Times=2.00 nsec=2×10 −9 s

Given :Speed of light =3×10 8 ms −1 Times=2.00 nsec=2×10 −9 sAs we know,

Given :Speed of light =3×10 8 ms −1 Times=2.00 nsec=2×10 −9 sAs we know,Distance covered =Speed×time

Given :Speed of light =3×10 8 ms −1 Times=2.00 nsec=2×10 −9 sAs we know,Distance covered =Speed×timeThe distance traveled is the product of speed and time.

Given :Speed of light =3×10 8 ms −1 Times=2.00 nsec=2×10 −9 sAs we know,Distance covered =Speed×timeThe distance traveled is the product of speed and time.Thus, in 2.00 nsec, the light will travel a distance of 3.00×10

Given :Speed of light =3×10 8 ms −1 Times=2.00 nsec=2×10 −9 sAs we know,Distance covered =Speed×timeThe distance traveled is the product of speed and time.Thus, in 2.00 nsec, the light will travel a distance of 3.00×10 8

Given :Speed of light =3×10 8 ms −1 Times=2.00 nsec=2×10 −9 sAs we know,Distance covered =Speed×timeThe distance traveled is the product of speed and time.Thus, in 2.00 nsec, the light will travel a distance of 3.00×10 8 ms

Given :Speed of light =3×10 8 ms −1 Times=2.00 nsec=2×10 −9 sAs we know,Distance covered =Speed×timeThe distance traveled is the product of speed and time.Thus, in 2.00 nsec, the light will travel a distance of 3.00×10 8 ms −1

Given :Speed of light =3×10 8 ms −1 Times=2.00 nsec=2×10 −9 sAs we know,Distance covered =Speed×timeThe distance traveled is the product of speed and time.Thus, in 2.00 nsec, the light will travel a distance of 3.00×10 8 ms −1 ×2.00×10

Given :Speed of light =3×10 8 ms −1 Times=2.00 nsec=2×10 −9 sAs we know,Distance covered =Speed×timeThe distance traveled is the product of speed and time.Thus, in 2.00 nsec, the light will travel a distance of 3.00×10 8 ms −1 ×2.00×10 −9

Given :Speed of light =3×10 8 ms −1 Times=2.00 nsec=2×10 −9 sAs we know,Distance covered =Speed×timeThe distance traveled is the product of speed and time.Thus, in 2.00 nsec, the light will travel a distance of 3.00×10 8 ms −1 ×2.00×10 −9 s=0.600m

I hope this will help you

stay safe and healthy

mark me as brainlaist (it is optional)