Math, asked by santa19, 12 hours ago

If The Speed Of light Is 3.0×10^8 m/s , Calculatethe distance covered by light in 2.00ns. ❎No Spam ​

Answers

Answered by SwanandoDas
3

Answer:

Distance covered = Speed x time

=3.0×10(8) ms-1 ×2.00

=3.0×10(8)ms-1 ×2.00 n s × 10(-9)s/1ns

=6.00×10(-1) m

= 0.600m

Step-by-step explanation:

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Answered by munnamanisha17
1

Answer:

Given :

Speed of light = 3X10⁸ ms ¹

Time= 2.00 nsec = 2X10 ⁹s

As we know

Distance covered= Speed X Time

The distance traveled is the product of Speed and Time

Thus in 2.00nsec, the light will travel a distance of

3.00 \times 10 ms \times 2.00 \times 10s = 0.600m3.00×10ms×2.00×10s=0.600m

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