If The Speed Of light Is 3.0×10^8 m/s , Calculatethe distance covered by light in 2.00ns. ❎No Spam
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Answered by
3
Answer:
Distance covered = Speed x time
=3.0×10(8) ms-1 ×2.00
=3.0×10(8)ms-1 ×2.00 n s × 10(-9)s/1ns
=6.00×10(-1) m
= 0.600m
Step-by-step explanation:
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Answered by
1
Answer:
Given :
Speed of light = 3X10⁸ ms ¹
Time= 2.00 nsec = 2X10 ⁹s
As we know
Distance covered= Speed X Time
The distance traveled is the product of Speed and Time
Thus in 2.00nsec, the light will travel a distance of
3.00 \times 10 ms \times 2.00 \times 10s = 0.600m3.00×10ms×2.00×10s=0.600m
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