Question

If the speed of light is 3.0×10(8) ms-1,calculate distance covered by light in 2.00ns.
pls ans. fast

Answer 1

Distance covered = Speed × time
=3.0×10(8) ms-1 ×2.00
=3.0×10(8)ms-1 ×2.00 n s × 10(-9)s/1ns
=6.00×10(-1) m
= 0.600m

Answer 2

Answer: Distance covered is 0.6 m.

Explanation:

The data given is as follows.

Speed of light = $3 \times 10^8 m/s$

Time = 2.00 nano seconds

Converting 2.00 nano seconds into seconds as follows.

                       1 nano second = $10^{-9}$ seconds

                      2.00 nano seconds = $2 \times 10^{-9}$ seconds

Using the formula, distance = $speed \times time$

Calculate the distance covered by light as follows.

          distance = $speed \times time$

                         = $3 \times 10^8 m/s \times 2 \times 10^{-9} s$

                         = $6 \times 10^{-1}$ m

                         = 0.6 m

Thus, distance covered is 0.6 m.