Chemistry, asked by duragpalsingh, 11 months ago

If the speed of light is 3.0 × 108 m s–1, calculate the distance covered by light in
2.00 ns

Answers

Answered by rohit1532

5

Answer:

Distance covered = Speed×Time = 3.0 × 108ms-1 × 2.00 ns

= 3.0×108ms-1×2.00 ns×10-9s/1ns = 6.00×10-1m = 0.600m

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