Chemistry, asked by narendramodi1615, 1 year ago

If the speed of light is 3.0 × 10⁸ m s⁻¹, calculate the distance covered by light in 200 ns.

Answers

Answered by samless123pcq81z
2

speed = Distance / time

distance = speed * time

distance = 3.0 * 10 ^ 8 * 200

distance = 600 * 10 ^ 8 m s^-1

   

Answered by Anonymous
8

HLO MATE HERE U GO

Speed of light = 3.0 × 10^8ms ^-1

therefore distance covered by light in 1 sec = 3.0× 10^8m

Distance covered by light in 2.00ns = 2.00 × 10^-9 s is 2.00× 10^ -9 × 3.0 × 10^8 = 0.6.

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