If the speed of sound in air is 336 metre per second, find the shortest length of a one end closed tube resonating with a fork of frequency 210 Hertz.
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ANSWER:
Hello dear,
● Answer -
L = 40 cm
● Explaination -
# Given -
v = 336 m/s
f = 210 Hz
# Solution -
Shortest wavelength of closed organ pipe is given by -
L = v / 4f
L = 336 / (4×210)
L = 336 / 840
L = 0.4 m
L = 40 cm
Therefore, shortest length of one end closed tube that can resonate with 210 Hz frequency is 40 cM.
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