if the speed of sound wave is 330m/s and its frequency is 0.4 khz. find distance between its consecutive compression and rarefactions
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speed of sound =330m/s Frequency =400 hz
distance between consecutive compression and rarefactions is the wavelength which is equal to speed /frequency •
wavelength = 330/400=0.825 A (Angstrom)
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distance between consecutive compression and rarefactions is the wavelength which is equal to speed /frequency •
wavelength = 330/400=0.825 A (Angstrom)
Hope you liked the answer.
please mark it as brainliest.
RisingFlame:
Is answer iin meters
??
if so then unit will be in meters
I don't know , I am not the questioner ,I was browsing , saw your unit used , so asked I think it should be in metres as angstrom is very small. isn't it?
yes its so
but in our book we have used Angstrom
okay but mostly angstrom used for atomic sizes and officialy meter is used , but its fine what can we do if book is showing this unit.
can you answer my recently given 2 question , i am kinda confused and stuck recently , help me out
where can i get them?
click on my name , see the option question asked and try to figure out the question i asked recently ,
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Answer
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speed of sound = 330 m / s
wavelength = 330 / 400 = 0.825
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speed of sound = 330 m / s
wavelength = 330 / 400 = 0.825
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