Question

If the speed of the light is approximately measured as 3.00 x 10^8 m/s, the distance it travels in 1.00ns is approximately

Answer 1

Explanation:

Given :

Speed of light =3×10

8

ms

−1

Times=2.00 nsec=2×10

−9

s

As we know,

Distance covered =Speed×time

The distance traveled is the product of speed and time.

Thus, in 2.00 nsec, the light will travel a distance of 3.00×10

8

ms

−1

×2.00×10

−9

s=0.600m