Question

If the speedometer of a bike riding along a straight road varues with time as given v(t)=(t+3)+t what will be its accelaration at time t=1 smsecond

Answer 1

Answer:

Acceleration = Rate of change of velocity

a(t)= dv/dt

Here v(t)= (t +3 )^2 +t^2

a(t)= dv/dy

=2(t+3)+2t when t=1 sec

=8 +2=10 unit / (second) ^2

Explanation:

clearly ATQ

v(t)=(t+3)^2 +t^2

we know

a(t)=dv(t)/dt

therefore

a(t)=2(t+3)+2t

a(1)=2(1+3)+2(1)

a(t)=10 m/s^2