Question

If the spinner is spun, what are the ODDS that the pointer lands on the number 6 or greater?

Answer 1

Answer:

If the spinner is spun, what are the ODDS that the pointer lands on the number 6 or greater?

2%

Answer 2

Answer:

The odds in favour of the pointer landing on the number 6 or greater is $\frac{3}{5}$

Step-by-step explanation:

The spinner has numbers starting from 1 and going till 8

Therefore, to land on a number greater than 6 or greater, it should land on either 6 , 7  or 8.

We know that Odds in favour = $\frac{P(success)}{P(failure)}$

Here, the success is getting a number greater or equal to 6

Therefore P(success) = $\frac{3}{8}$

We know that $P(A) + P(\bar A) = 1$

=> P(success) + P(failure) = 1

=>  $\frac{3}{8}$ + P(failure) = 1

=> P(failure) = 1 -  $\frac{3}{8}$

                    = $\frac{5}{8}$

Therefore, odds in favour = $\frac{\frac{3}{8}}{\frac{5}{8}}$

                                           = $\frac{3}{5}$

Therefore, the odds in favour of the pointer landing on the number 6 or greater is $\frac{3}{5}$