If the square of hypotenuse of a right angled isosceles triangle is 578 cm², then
find the length of each of its equal sides.
Please answer correctly
Answers
Answer:
17 cm
Step-by-step explanation:
Let the equal sides of the triangle be x.
Then according to pythagoras theory
The side of the triangle is 17 cm.
Hope it helps you.
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Ans17Answer:
17 cm
Step-by-step explanation:
Let the equal sides of the triangle be x.
Then according to pythagoras theory
\begin{gathered} {x}^{2} + {x}^{2} = 578 \\ {2x}^{2} = 578 \\ {x}^{2} = 578 \div 2 \\ {x}^{2} = 289 \\ x = \sqrt{17 \times 17} \\ x = 17\end{gathered}
x
2
+x
2
=578
2x
2
=578
x
2
=578÷2
x
2
=289
x=
17×17
x=17
The side of the triangle is 17 cm.
Hope it helps you.
Pls mark branliest.wer:
17
Step-by-step explanation:
Let the equal sides of the triangle be x.
Then according to pythagoras theory
\begin{gathered} {x}^{2} + {x}^{2} = 578 \\ {2x}^{2} = 578 \\ {x}^{2} = 578 \div 2 \\ {x}^{2} = 289 \\ x = \sqrt{17 \times 17} \\ x = 17\end{gathered}
x
2
+x
2
=578
2x
2
=578
x
2
=578÷2
x
2
=289
x=
17×17
x=17
The side of the triangle is 17 cm.
Hope it helps you.
Pls mark branliest.:
17 cm
Step-by-step explanation:
Let the equal sides of the triangle be x.
Then according to pythagoras theory
\begin{gathered} {x}^{2} + {x}^{2} = 578 \\ {2x}^{2} = 578 \\ {x}^{2} = 578 \div 2 \\ {x}^{2} = 289 \\ x = \sqrt{17 \times 17} \\ x = 17\end{gathered}
x
2
+x
2
=578
2x
2
=578
x
2
=578÷2
x
2
=289
x=
17×17
x=17
The side of the triangle is 17 cm.
Hope it helps you.
Pls mark branliest.
Answer:
17 cm
Step-by-step explanation:
Let the equal sides of the triangle be x.
Then according to pythagoras theory
\begin{gathered} {x}^{2} + {x}^{2} = 578 \\ {2x}^{2} = 578 \\ {x}^{2} = 578 \div 2 \\ {x}^{2} = 2{17 \times 17} \\ x = 17\end{gathered}
x
2
+x
2
=578
2x
2
=578
x
2
=578÷2
x
2
=289
x=
17×17
x=17
The side of the triangle is 17 cm.
Hope it helps you.
Pls mark branliest.