Question

If the square of the difference of the 0 of the quadratic polynomial fx=x²+px+45 is equal to 144 find the value of P


answer plz (ب_ب)​

Answer 1

Answer:

Let α,β be the zeroes of the given quadratic polynomial f(x)=x

2

+px+45

∴α+β=−p,αβ=45

It is given that, (α−β)

2

=144

⇒(α+β)

2

–4αβ=144

⇒(–p)

2

–4×45=144

⇒p

2

–180=144

⇒p

2

=144+180

⇒p

2

=324

⇒p=±

324

∴p=±18

Step-by-step explanation:

hope this may help you have a great day

Answer 2

Answer:

hope it's hlp you

Step-by-step explanation:

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