Question

if the square of the difference of zeros of the quadratic polynomial f(x) = x^2 + px + 45 is equal to 144 find the value of p.

pls ans asap
its urgent

Answer 1

Answer:

D=b^2-4ac

=p

(p)^2-4(1)(45)

p^2-180=144

p^2=144+180

p^2=324

p=

$\sqrt{324}$

p=18