If the square of the distances between the points (12, 5)and (x, 3)is 29, find the value of x.
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Answer:
The values of x are 17 and 7
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distance between any two points is given by
√((x2-x1)^2+(y2-y1)^2),
therefore,distance between (12,5)&(X,3)is
√((x-12)^2+(3-5)^2),
given that ,(√((x-12)^2+4))^2=29,
=>(x-12)^2=25,
=>x-12=+/-5,
=>x=17or7
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