Question

If the square of the hypotenuse of an isosceles right triangle is 128 cm^2,find the length of each side.

Answer 1

Step-by-step explanation:

Let the equal sides of the triangle be x

(since it is a isosceles triangle)

By Pythagoras theorem

(hypotenuse)^2 = (base)^2 + (perpendicular)^2

=> 128 = x^2 + x^2 (since it is a isosceles triangle)

=> 128 = 2x^2

=> 128/2 = x^2

=> x^2 = 64

=> x = 8 cm

therefore the length of each equal side are 8cm

I hope this will help you...

Answer 2

Answer:

8 cm

Step-by-step explanation:

Let the equal sides of the triangle be x

(since it is a isosceles triangle)

We can use use Pythagoras theorem for solving this problem.

(hypotenuse)^2 = (base)^2 + (perpendicular)^2

• 128 = x^2 + x^2 (since it is a isosceles triangle)

• 128 = 2x ^2
• 128/2 = x^2
• x^2 = 64
• x = 8 cm  

I HOPE THIS HELPS YOU :)

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