Question

if the square of the zeroes of the polynomial f(x)= 2xcube-3kxsquare+4x-5 is 6,then the value of k is??​

Answer 1

Answer:

2x square-3kxsquare+4x-5

put x = 6

2(6)square -3k(6)square+4(6)-5

2(36)-3k(36)+24-5

72-108k+ 19

-108k = -19 -72

-108k = -91

k = -91/-108