Question

if the square of two positive integers differ by 1987.Then sum of these integers is .

Answer 1

To solve these kind of problems, just read the question carefully and proceed accordingly “step by step”.

Assume the consecutive integers be:  x  and [ x+1 ]

Now, according to the question:

(x+1)^2−x^2=1987

x^2+2x+1−x^2=1987  [applying (a+b)^2 identity ]

2x+1=1987

x+(x+1)=1987

Hence,

The sum of two integers  =x +(x+1) = 1987