Question

If the squared difference of the zeroes of the quadratic polynomial 2
x px + + 45 is equal to 144, find the
value of P​

Answer 1

Answer:

+18

Step-by-step explanation:

Let α,β be the zeroes of the given quadratic polynomial f(x)=2

x +px+45

∴α+β=−p,αβ=45

It is given that, (α−β)

2 =144

⇒(α+β) 2 –4αβ=144

⇒(–p) 2 –4×45=144

⇒p 2 –180=144

⇒p 2 =144+180

⇒p 2 =324

⇒p=± 324

∴p=±18