Math, asked by legendarybishnu, 23 days ago

If the squared difference of the zeroes of the quadratic polynomial f(x) = x2
+ kx
+ 30 is equal to 169, find the value of k & the zeroes.​

Answers

Answered by aryanreddy463
1

Answer:

17

Step-by-step explanation:

x^2-y^2=169

x+y=-k(sum of roots=(-b/a)

xy=30(product of roots=c/a)

(x+y)^2-4xy=169(x^2-y^2=(x+y)^2-4xy)

(-k)^2-120=169

k^2=289

k=17

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