If the squared difference of the zeroes of the quadratic polynomial f(x) = x2
+ kx
+ 30 is equal to 169, find the value of k & the zeroes.
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Answered by
1
Answer:
17
Step-by-step explanation:
x^2-y^2=169
x+y=-k(sum of roots=(-b/a)
xy=30(product of roots=c/a)
(x+y)^2-4xy=169(x^2-y^2=(x+y)^2-4xy)
(-k)^2-120=169
k^2=289
k=17
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