Question

if the squared difference of the zeros of the quadratic polynomial f of x = 2 X square + PX + 45 is equals to 144 find the value of p​

Answer 1

Answer:

A=alpha,b=beta

we can let ' a ' and ' b ' be the roots of the quadratic polynomial f (x) = x² + px + 45

∴ we can write a+b= -p (sum of the roots)

we can also write ab=45(product of roots)

it is given that,

∴ (a + b)² –4ab=144

⇒ (– p)² –4×45=144

⇒ p ²–180=144

⇒ p²= 144+180

⇒p²=324

⇒p= ±√324

∴p=±18

Answer 2

Step-by-step explanation:

let alpha and beta be zero of polynomial.