if the squared difference of the zeros of the quadratic polynomial f (x) = X square + px + 45 is equal to 144 find the value of p
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f(1)=1square+98(1)+45=144
=1+98+45=144
99+45=144
so that you can put 98
=1+98+45=144
99+45=144
so that you can put 98
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Hope you will correct my answer.
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Please mark me as a brainliest.
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