Question

if the squared difference of zeros of the quadratic polynomial P of x = x square + px + 45 is equal to 144 then the find of value of p

Answer 1

Let the zeros be a and b.

Sum of zeros ( a+ b ) = - b/a= -p

Product of zeros (a×b) = c/a = 45

A/Q ( a - b ) ^2 = 144

=> a^2 + b^2 - 2ab = 144

=> (a +b ) ^2 - 2ab - 2ab = 144

=> (-p)^2 -4 × 45 = 144

=> p^2 - 180 = 144

=> p^2 = 144 +180

=> p^2 = 324

=>p = +/- 18 .

Answer 2

hi it's the answer ..............