If the standard electrode potential of cu2+/cu electrode is 0.34 v, what is the electrode potential of 0.1 M concentration of cu2+ ?
Answers
Answer:
If the activity of the hydrogen ion is 1 mol/l (pH=0) and hydrogen gas is bubbled into the solution so that partial pressure of hydrogen is 1 atm, the electrode potential is defined as zero volts at any temperature: E0=0.000 V.
The electrode potential of Cu2+/Cu couple in the given conditions is 0.31045 V.
- According to the Nernst equation:
E = Eo - (RT/nF) ln{[P]/[R]}
where, Eo = standard electrode potential
E = electrode potential
R = gas constant
T = temperature
n = number of electrons
P = activity (concentration) of products
R = activity (concentration) of reactants
- At room temperature, E = Eo - (0.0591/n) log{[P]/[R]}
- Substituting the values as: n = 2, [P] = 1 (since for metals, activity = 1), [R] = 0.1 (given), Eo = 0.34 V (given)
E = 0.31045 V