Question

If the standard quadratic form of the equation 5/y+2−3/y−3=6 is ay2+by+c=0, which of the following could be the possible values of a, b and c?

Answer 1

Step-by-step explanation:

ANSWER

ay

2+ay+3=0

as 1 is root then

⇒a(1)

2+a(1)+3=0

⇒a+a=−3

⇒2a=−3

⇒a=− 23y

2+y+b=0

⇒(1)

2+1+b=0

⇒2+b=0

⇒b=−2

∴ab=−

23×−2=3