Question

If the starting address of an float array Arr[10][10] is 2000, what would be the memory address of the element Arr[5][6]?

Answer 1

Address=B+W[n(I-Lr) + (J-Lc )]

B is the base address

W is the element size in bytes

n is the number of columns

Lr is the first row number

Lc is the first column number

B=2000

Lr=0  

Lc=0  

W=4  

n=10

I=5

J=6

using formula,

address= 2000+4[10(5–0) + (6–0)]

= 2000+4[50+6]

=2000+4[56]

=2000+224

=2224

Answer 2

The answer to he question (Assuming for a c Compiler) with 4 bytes for a float variable the memory address would actually increment by 4 bytes for each consecutive element of array.

So if the first address is 2000, then for every consecutive element, the address would actually increment by 4, thus,

[0][0]=2000 -[0][9]=2036

[1][0]=2040 -[1][9]=2076

[2][0]=2080 -[2][9]=2116

[3][0]=2120-[3][9]=2156

[4][0]=2160-[4][9]=2196

[5][0]=2200 [5][1]=2204 [5][2]=2208 [5][3]=2212 [5][4]=2216 [5][5]=2220

Therefore, the answer to your question is [5][6]=2224