Question

If the stone is thrown vertically up and it is caught after time 't' second then the maximum height reached by it is ?

Answer 1

Explanation:

the height is depend on the mass of stone if the mass of stone 1 kg then height = 1x9.8 by time the answer will come

Answer 2

Answer:

H=ut+1/2at²

But since t is for both throwing and catching.

Hence for throwing time will be half i.e. t/2

So H=ut/2+1/2g×(t/2)²

{here a=g} and taking it 10

=ut/2+1/2×10×t²/4

=ut/2+5t²/4=(2ut+5t²)/4

Explanation:

Brainliest please